2x^2+3x-1890=0

Solution for 2x^2+3x-1890=0 equation:

2x^2+3x-1890=0

a = 2; b = 3; c = -1890;
Δ = b2-4ac
Δ = 32-4·2·(-1890)
Δ = 15129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15129}=123$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-123}{2*2}=\frac{-126}{4}
=-31+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+123}{2*2}=\frac{120}{4}
=30
$